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Interview Question Fizz Buzz

Last update: 2/6/2017 4:50:00 AM

By Fatih KABAKCI

The problem is to return a list that has corresponding string values between 1 and number that has been provided by user. However, the thing is, while index is multiple of 3, the value should be Fizz, if index is multiple of 5, the value should be Buzz. Both condition includes the string FizzBuzz.

Problem #412 - Fizz Buzz

Description: Write a program that outputs the string representation of numbers from 1 to n.

But for multiples of three it should output "Fizz" instead of the number and for the multiples of five output "Buzz". For numbers which are multiples of both three and five output "FizzBuzz".

Difficulty: Easy

Solution in Java

package com.fatihkabakci.Easy.FizzBuzz;

import java.util.ArrayList;
import java.util.List;

/**
 * 
 * @author fkabakci
 * Problem Description: Write a program that outputs the string representation of numbers from 1 to n.
 * 
 * But for multiples of three it should output "Fizz" instead of the number and for the multiples of 
 * five output "Buzz". For numbers which are multiples of both three and five output "FizzBuzz".
 * 
 * Example:
 * 
 * n = 15,
 * Return:
 * [
 *   "1",
 *   "2",
 *   "Fizz",
 *   "4",
 *   "Buzz",
 *   "Fizz",
 *   "7",
 *   "8",
 *   "Fizz",
 *   "Buzz",
 *   "11",
 *   "Fizz",
 *   "13",
 *   "14",
 *   "FizzBuzz"
 *  ]
 * 
 * Solution:
 * 1. Traverse list.
 * 2. Check each element if multiple of 5 & 3, or only 3, or only 5, then
 * 	  add corresponding string.
 * 3. Otherwise, add number.
 */
public class Solution {
	public List<String> fizzBuzz(int n) {
		List<String> list = new ArrayList<String>();
        for(int i = 1; i <= n; i++) {
        	if(i % 3 == 0 && i % 5 == 0)
        		list.add("FizzBuzz");
        	else if(i % 3 == 0)
        		list.add("Fizz");
        	else if(i % 5 == 0)
        		list.add("Buzz");
        	else
        		list.add(i + "");
        }
        return list;
    }

	public static void main(String[] args) {
	}
}

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